doh......................... i 4gt.............. 2 coils banege............so multiplid by 2 hoga.............
kash 26th ko aisi galti na karu ........... :'(
A heating coil is labeled 100 W, 220 V. The coil is cut into two equal pieces, which are joined in parallel to the same source. The energy now liberated per second is
Q87 A heating coil is labeled 100 W, 220 V. The coil is cut into two equal pieces, which are joined in parallel to the same source. The energy now liberated per second is
a) 25 J/s
b) 50 J/s
c) 200 J/s
d) 400 J/s
Your Answer: (c)
Correct Answer: (d)
Score: -1
as the coil is cut the resistance of each piece will be halved and now the total power will be the contribution of both
intitally we have
(220)2/R=100
finally the total power=
(220)2/(R/2)+ (220)2/(R/2) (As the voltage across both the coils are same)
=4*(220)2/R=4*100=400
doh......................... i 4gt.............. 2 coils banege............so multiplid by 2 hoga.............
kash 26th ko aisi galti na karu ........... :'(