Test:39 QNo:6

find dy/dx where y=sec-1x2

2 Answers

1
sumit_kumar ·

Q6 find dy/dx where y=sec-1x2

a) 2/x√(x4-1)
b) 2/|x|√(x4-1)
c) -2/|x|√(x4-1)
d) -2/x√(x4-1)

Correct Answer: (a)

why cant the ans be b)

1
" ____________ ·

it can also be ( b ) since the quadrant is not specified

Your Answer

Close [X]