FULL TEST 1 DOUBTSSSS

Manish Sir,
QUE 68,69 in paper will be graced or sumthing?

Wen will our marks alter? or hav they already bn altered

STATEMENT-II: When the motion is uniform, acceleration is zero

motion is uniform implies velocity is constant not acceleration is constant....

I HOPE THIS COULD CLEAR YOUR DOUBTS
Uniform, or constant, acceleration is a type of motion in which the velocity of an object changes equal amounts in equal time periods. An example of an object having uniform acceleration would be a ball rolling down a ramp. The object picks up velocity as it goes down the ramp with equal changes in time. The most frequently cited example of uniform acceleration however is that of an object in free fall.

i think u are considering only CIRCULAR MOTION
BUT IT IS GENERAL HERE

SORRY TO DISAGREE
BUT Q5 IS PERFECT

HINT: THE POINT OF INTERSECTION OF THE LINES DOESNT GIVES X₁,Y₁
WE HAVE TO FIND X₁,Y₁ FROM IT

ie post 44, 47

Sir, many other doubts also, pl. see my posts

THAK u [1]

k k.... no probs [1]

Q81 Match the following
(81) Mn2+ (a) Diamagnetic
(82) Cu+ (b) Paramagnetic
(83) Ni2+ (c) Coloured compounds
(84) Cr3+ (d) Magnetic Moment=2.82 BM

Your Answer: c And a
Correct Answer: c And b
Score: -1
Explaination :

Q82 refer prev ques
Your Answer: c And b
Correct Answer: a
Score: -1
Explaination :

Q83 refer prev ques
Your Answer: c And b
Correct Answer: d And c And b
Score: -1
Explaination :
Q84 refer prev ques
Your Answer: d And c And b
Correct Answer: c And b
Score: -1
Explaination :

SIR JI
YEH KYA HO GAYA[16]
MAINE TEST 1 MEIN MATHS KE SAARE MCQ KIYE THE
I AM DEFINITLY SURE

BUT THEY ARE MARKED AS NOT DONE AND R PUT IN A YELLOW BOX[2]

now in first paper:

Q21 comprehension for ques 21-23

The function given as f(x)=0∫x 4t(t^2-1)

it has global minimum at x=
Your Answer: none of these
Correct Answer: none of these
Score: 4.00
Explaination :
it is at x±1

Q22 the value of global minimum is
Your Answer: 0
Correct Answer: -1
Score: -1
Explaination :
it is -1

Q23 The maximum value of the function is at x=
Your Answer: 0
Correct Answer: none of these
Score: -1
Explaination :
it is at x±∞

how is global min value not 0 ???

and also q.23....

all the above are from second paper

Q55 A satellite of mass m is orbiting the earth at a height h from its surface.(mass of earth is M and its radius is R)

(55) Kinetic energy of the satellite (a) -GMm/(R+h)

(56) Potential energy of the satellite (b) GMm/2(R+h)

(57) Total energy of the satellite (c) -GMm/2(R+h)
(58) Energy spent to pull the satellite out (d) 2GMm/(R+h)
of the earth's gravitational fiels

i want explanation for the 58th question.

SECOND PAPER:

Q51. mathc the following: For motion in a straight line

(51) Acceleration (a) is always along the motion of particle
(52) Speed (b) maybe along the motion of the particle
(53) Velocity (c) is always opposite to motion of particle
(54) Retardation (d) nothing can be said about direction

Your Answer: a
Correct Answer: b
Score: -1

Y ACCELERATION 'MAY' BE ALONG MOTION OF PARTICLE.??????

if it is in the ulta direction, then it is 'retardation' isnt it ?

omg!

got so many dbts!!

wil post tomorrow :'(

Q60 STATEMENT-I: Addition of bromine to trans-2-butene yields meso-2,3-dibromobutane.
STATEMENT-II: Bromine addition to an alkene is an electrophilic addition.
Your Answer: d
Correct Answer: b
Score: -1
Explaination :
its not the correct reason

1st of all : stereochemistry of addition not included in jee syllabus.

2nd of all : wat is the reason pls tell.

dun feel anything right now tapan....

am toooooooooooo tensed with surface tension ...

pls dun mind but i will tell u tomorrow if no1 tells :P

SKY : wat do u feel abt my doubts in PAPER 1, ie post 1 & 3

q.12 ... second paper..

where is the equality sign ????????????????????

oh k....hmmmm........ isi liye mujhe none of these aaya..... [3]

wat abt the other two?

FT1 Paper 2 mein Q17 mein guys ke love is askd, but da soltn gives gulz ka Lov ([3])
pl. chk dat que, mayb sum printin mist.

arey sum kahah hai yaar

QUE 68 mein mere ko ans 1.31 nahi aata hai... [2]

btw R kya liya aapne
?

0.02 Mole fraction of acetic acid in benzene given a solution having freezing point 277.4 K. Freezing point of benzene is 278.4 K and heat of fusion of benzene is 10.042 kJ/mol. If molarity of solution is equal to molality, and acetic acid is found in equilibrium with its dimer.

FIND Kf

Kf kaise aaya bhai log???

k = RT²/1000L_f

= R 278.4²/10042