Differentiation

I Differentiated it
d tan(cos-1x)d x
hint given is
=>tanθ=11+x2
which I think is not possible in any way
Answer given inthe book is
= -3x(1+x2)-3/2

the way i did the sum is as follows

cos-1x=θ
=>tanθ=1-x2x
.'.
= x d1-x2dx - √1-x2dxdxx2
= -1x21-x2 ................(ans)

P.S. Suggest the correct ans

1 Answers

71
Vivek @ Born this Way ·

You didn't looked at the right side of the expression you had differentiated.

I.e., tanθ = 1-x2x ........I

When You differentiate, the right side is as you have shown but,

sec2θ . dθdt = expression you have written ....

Now, Find sec2θ . dθdt from relation I

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