Error Analysis... 2

A wire of length l=6Â±.06 cm and radius =0.5Â±0.005 cm and mass m=0.3Â±0.003 gm.

maximum percentage error in density is ?

3 Answers

density = mass / Ï€ r² l
% error in density = % error in mass +2* % error in radius + % error in length
= 1 % + 2* 1% + 1% = 4 %

D = M/V
D= M/l*2âˆ©R²

Therefore % error is

E = {0.06/6 + 0.005/0.5+ 0.003/0.3) *100
E = [0.01 + 0.01*2 + 0.01) *100

E = 4%

Is it rite sir?

yup this is right :)

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