1how to do the first one
9 Answers
1dude first is easy sum conserve energy.thts the hint now start your problem with basics and certainly u vl end up with correct ans
1Ans 2)6 kg
we find that when both ice and water are at 0°C still the water can supply 80000 cal of heat enough to melt 1000g(1kg) of ice to water.
so total amt of water finally at 0°C is (5+1)kg=6 kg
1α=3 acc. to me
2 capacitors in parallel and one in series, u have to find v across the parallel one.
16
20000 cal from -20 to 0 ice
100000 cal from 20 to 0 water
80000 cal left
enough to melt 1 kg ice to water
so
1kg ice 6kg water
1Q1...TAPAS...U RE RONG
Q2...6 IS DA ANS MANY OF US R GETTIN...BUT ANS GIVN 2
11Potential of the 1st plate and the last plates are 0.
Now total charge on 3rd plate is 0. Let the charge on 4th plate and 1st plates be q' and q".
P.D of 1=0 implies q'=q3.
Similarly P.D of 4th plate is 0, so q" is found out....
Now see V1-V4=(V1-v2)+(V2-V3)+(V3-V4)=0....since both V1=V2=0.
Since net charge on V3=0, we can get the middle term i.e. V2-V3.
Pls correct me if wrong.
1here considering only plates 2 & 3
E(region bet 2 & 3) = Q/2eA
so, V = Qd/2eA
pls crrect if i m wrong