Zero Error.

If the zero error is given by +.0002 units

and the final reading on a measuring device is 1 unit

What is the correct length?

15 Answers

1
Akand ·

0.9998

62
Lokesh Verma ·

Why is zero error substracted?

1
Akand ·

its +.............so we need to subtratc

11
Mani Pal Singh ·

0.9998
this is due to the fact thatbecause 0 error is always subtracted from the measured length

62
Lokesh Verma ·

that is my question!

It comes from the definition of zero error!

1
Akand ·

manipal..............its not alwasys subtracted.......

1
Akand ·

If the question was..........

If the zero error is given by -.0002 units

and the final reading on a measuring device is 1 unit

then d ans is 1.0002

11
virang1 Jhaveri ·

Zero Error is the deviation of the reading from zero. Therefore If the deviation is +x. The reading will be more by x. Therefore it has to be subtracted

62
Lokesh Verma ·

@virang
what do you mean deviation of the reading from zero!

least count has nothing to do with reading i guess.

I understand the "bhavna" of your answer though..

1
Akand ·

so my ans is rite naa??????

11
virang1 Jhaveri ·

Sir , I am not talking of least count out here. The explanation i gave is for the question why do we subtract the zero error .

11
Anirudh Narayanan ·

The zero error shows how much more or how much less the reading is, from the real value.....

When we get the head scale reference line above the 0 line:

There should have been some more rotations to make the coincidence but some internal problem caused it to 'tick' well before (hence negative 0 error) ..... so an xtra amount must be added to the reading to give the exact value (hence positive 0 correction)

For the other case (0 coming above the ref. line..) the problrm caused the 'tick' sometime after it should have come (hence positive 0 error) and so some value has to be taken off so as to get the correct reading (Hence negative 0 correction)

1
Philip Calvert ·

i think what virang is sayong is that
a +..... zero error means that when the reading should have been zero ; it was "....." more than zero

then obviously the reading at any other point must also be "......" more than the actual reading at that point (unless the device contracts or expands :D )

hence we subtract "....." from the observed reading

11
virang1 Jhaveri ·

Thank you Philip for understanding me

24
eureka123 ·

imp fact

zero error is always algebraically subtracted
and zero correction is always algebraically added[1][1]

if zero of scale lies to right of zero of main scale then positive error and if left then negative error.[1]

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