An empty mind is devil's workshop :P

\int_{-1}^{2}{x^2} dx

whats the need to integrate ?????jsut fill in values..
(2)^2-(-1)^2

=4-1
=3

[3][3]

23 Answers

4
UTTARA ·

No Sanchit My B'day is on 31st Feb (never saw my profile ??) And both r not the answers to the riddle though

I am not posting the ans

Let us w8 for any other idle brain

1
adhithyan ·

@johndover..... math will b fun if u try to do something like this...maybe u will end up with a great formula or a principle that could fetch u the ABEL prize!!!!!

1
Linkin Park ·

you guys are crazy. why are you all disrespecting maths?

36
rahul ·

@adhityan - you are correct if on earth 0/0 = 1 :P

1
adhithyan ·

consider
a=b
*a on both sides

a2=ab

subtract b2 on both sides..

a2-b2=ab-b2

( a+b)(a-b)=b(a-b)

(a+b)=b

sustituting b in the place of a (a=b)

b+b=b
2b=b
2=1

lolzzzzzzzzzzzzzzzzzzzzzzzzz

1
var ·

put a decimal point between 5 and 9...so it becomes 5.9...

11
vaibhav sharma ·

your birthday is on 31 december
The day before yesterday (December 30) you were 25.
you turned 26 on December 31.
you talked about it on January 1. That year you would become 27, so "next year" you would be 28.

1
Parul Kohli ·

acc. to Q ur bday is on 31st december

4
UTTARA ·

yup r8 ans :)

1
gordo ·

lol. the answer to this is moving the 2 of 102 up, to make it 102
anyways, iitjee results not coming in time has surely made u guyz a bunch of idle lot. :D
cheers!!

4
UTTARA ·

No eureka u cant do that

I said by interchanging digits not signs

24
eureka123 ·

@ #11

101 - 102 = 1

interchange '-' and '=' signs to get 101=102-1 [1]

24
eureka123 ·

another one...this has even more blunders.... [3]

\int \frac{1}{x+1} dx

\int \frac{1}{x}+ \frac{1}{1}dx=\int\frac{1}{x}dx +\int\frac{1}{1}dx =logx+log1=log(1+x)

1
sanchit ·

ur birthday then is 29 feb :)

4
UTTARA ·

What mathematical symbol can be placed between 5 and 9, to get a number greater than 5 and smaller than 9?

4
UTTARA ·

The day before yesterday I was 25 and the next year I will be 28. This is true only one day in a year. What day is my birthday?

4
UTTARA ·

Rectify the following equality 101 - 102 = 1 by moving just one digit.

u can move the diigits anyway though [3]

1
madhumitha harishankar ·

coz seems like eureka only asked abuot idle guys :P

49
Subhomoy Bakshi ·

LOL...HAHAH!!

AFRIAD??? lol why??

1
madhumitha harishankar ·

haha no. im idle too,...but not a guy, im afraid :P :P

24
eureka123 ·

no rpelies ????
am i the only idle guy these days ???

24
eureka123 ·

every complex no. is real [3][3]

z=re^{i \theta}

when θ≠0,let α=eiθ
\alpha ^{2 \pi /\theta}=(e^{i \theta})^{2 \pi /\theta}=e^{i 2\pi}=1

=>\alpha= 1^{\theta /2\pi}=1

hence proved [3]

24
eureka123 ·

\sum_{1}^{\infty}{\frac{1}{(k+1)(k+2)}}

whats hte ans ???

can it have two ans ???

looks noo...but there are...

1)put k =1,2...

1/6 +1/12 + 1/20 +... =(1/2 -1/3)+(1/3 -1/4)+(1/4-1/5)+....=1/2

2)again same thing but diff way
1/6 +1/12 + 1/20 +...=(1-5/6)+(5/6-3/4)+(3/4-7/10)+...=1 [3][3]

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