Q) (A)( yellow coloured solution ) changes to light green coloured solution (B), on passing H2S gas.
(A) and(B) both give white precipitate with BaCl2 solution, insoluble in conc. HCl . (A) gives blue
coloured precipitate (C) with K4[Fe(CN)6] ,but (B) does not. find (A),(B),(C).
24both give white ppt with BaCl2 => SO42- is there in both
A gives blue colored ppt. with K4[Fe(CN)6] => Fe3+
=> A is Fe2(SO4)3
and C is Fe4[Fe(CN)6]
1ya,i know C is Fe4[Fe(CN)6]3( PRUSSIAN BLUE) , but A is having Fe3+ cation but not the sulphate ion.second statement in the question is the confusing one
24My yesterday's view about BaCl2 test was biased with sulfates...but the reality is that sulphates,sulphites and chromates give the test
=> A is Fe2(SO4)3
or Fe2(SO3)3
or Fe2(CrO4)3
moreover Fe2(CrO4)3 is yellow in color..so A could be Iron(III) chromate[1]
1ya,eure.perhaps, u r right. actually,answer is given: A is FeCl3.but,i don't think its anyway near.i'm satisfied with ur answer.thnx,dude