A particle is projected at an angle of 60° with speed 10√3 from teh point A as shown in teh fig......at the same time the wedge is made to move with speed 10√3 towards rigth as shon in the fig.....then time after which particle will strike the wedge is???
g=10m/s2
not a doubt
1i think the particle will strike the wedge when the vel. of particle is equal to the rel vel .of the particle..or we can say rel. vel. is zero..
1Discussing motion of Ball from the frame of Wedge .
Vel. of ball perpendicular to wedge = 5√3
now gravitational force perpendicular to wedge = gCos 30 = g√3/2 = 5√3
let the ball strike the wedge after 't' sec
=> -5√3=5√3-5√3t (v=u+at)
=>t=2 sec
the particle strikes the wedge after 2 sec.
