JUST SEE THAT friction=2g=20NNORMAL REACTION=40NHENCE,ABOVE WE KNOW THAT SYSTEM IS IN RESTSO AT MIDPOINT C Total friction distance from c is 10 and the normal reaction assume x then 20*10=N*x solving this we get x=5cm
A cube of mass 2kg is held stationary against a rough wall by a force F=40N pass through centre C.Find perpendicular distance of normal reaction between wall and cube from point C.Side of the cube is 20cm.

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3 Answers
eureka123
·20090704 22:57:21
have u drawn fbd????
if yes then answer will be in front of u...[1][1]
nix_13 12
·20090704 23:11:35
hmmmmm.........i did draw FBD............but still didnt get.............
Physics Wallah
·20190202 03:40:29