assertion n reason
statement 1 ;acceleration due to gravity gos on decreasing as we goes frm equqtor to pole
statement 2:a part of weight is used to provide the centripetal force for rotating the body abt n-s axis of earth
1here is d explanation...
d rotation of earth about it's N-S axis causes centrifugal force which is in opposite direction to gravity... so a body will weigh less at equator when compared to other parts of earth...
now temme d answer...!!!
1yep...
earth is in oval shape, bulged at poles... so d gravitational attraction will b more at poles when compared to equator, as more mass is concentrated in relatively less area at poles whereas it is distributed over a large area at equator...
got...!!!
1gravitational force i understood bt acc due to gravity is GM/R2na to mass distribution kahan se aaya sry i might be looking →silly bt still confused
1yaar, tumne he tho answer bataayaa... gravity is ntng but d force of attraction b/w earth and body rite... so if mass is distributed over a small region, it'll attract d body effectively when compared to d mass distributed over a wide area...
since it is distributed over a small area at poles, it'll attract d body more when compared to at equator...
1for example, consider a magnet in d shape of a rugby ball... upon several experiments, u'll observe dat magnet attracts an object more strongly at d bulged parts while compared wid d flat area... dis is d same phenomena...
well, it does not vary on a large scale... but still, it's li'l more at poles compared to equator... :)
1yeahhh... acceleration due to gravity g=GM/R2... rite...
here v consider M as d mass of earth and is assumed to be constant... generally while solving problems...
but here... it's taken to b varying...!!!
well, i'll explain u in other way round... an easier way i hope...
from statement-2, it's evitable that in order to over-come d centrifugal force due to rotation of earth, a part of gravitational force on body is taken as centripetal force rite... so d effective attraction decreases... whereas at poles, there's no centrifugal force acting... hence d effective gravity will b more...
hope dis clears ur doubt... :)
(forget d previous explanation, to avoid confusion...)
1shit i dunno wat i ws thinking .thanks a lot :) now i got it n realised my mistake.thanks again