h = atanθ(1 - aR)
h = 2atanθ(1 - 2aR)
Therefore, R = 3a
find tanθ from one of the equations.
find v from equation of range.
A particle is projected from a point on the level ground and its height is h when at horizontal distance a and 2a from its point of projection. Find the velocity of projection.
√[g(9h2 + 4a24h]
h = atanθ(1 - aR)
h = 2atanθ(1 - 2aR)
Therefore, R = 3a
find tanθ from one of the equations.
find v from equation of range.