2gk
- Akash Anand Wrong answer I guessUpvote·0· Reply ·2014-03-21 23:08:25
At time t=0 string A is cut, then what will be the maximum compression in the spring if spring constant is K.(Assume surfaces are smooth and initially spring was at its natural length)
2gk
At the mean position, Kx=2g; x=2gK
2gx=12Kx^{2} +K.E (Using energy conservation)
K.E is the kinetic energy of the two block system ,individually they each have kinetic energy=K.E2
Just after that the string would become loose,So the upper block would continue to move with that velocity,
So at max. compression(h) the kinetic energy of system=K.E2
2gh=12Kh^{2} +K.E2
Solving we get,h=(2+âˆš2)gK
IS IT CORRECT?
Niraj..I am not able to find the fallacy, but the given answer is far different from this. Given answer is 0.45m .