shm shm iit

In a S. H . M , the total total energy of a particle is always constant and greater than zero . Hence , the option " ( a ) " is incorrect .

If , " E > V₀ " , then , as the paticle possesses greater total energy , so , instead of performing S . H . M , it will tend to go towards infinity .

So , the only possibility is : - V₀ > E > 0 .