1see u find the roots of the equation, which come out to be1, 2 + √3 i and 2- √3i
and then put them in the equation, and then we get 1/w^2 + w + w, which is 3/w^2 or 3w
49 Answers
11heyy...everybody says arihant is crap...should we follow it for bits??
1height of a man is 5.87532 ft .measrment is crrect upto 3 digits .the crrect hgt is
1. 5.86 2. 5.88 3. 5.87 4. 5.80
ans 1...................plz tell me how?
1how can be one since it is already mentioned that height is 5.87___ ft
so 5.87____ se 5.86 ___ kaise hogaya..........
i thnk it shuld be (2)
1THE NO OF REAL ROOTS OF
{ ( 2 x - 3 ) / (x -1) } + 1 = ( 6x2 -x -6)/ (x-1)
a. 1 b. 2 c. 0 d. none of these
ans d...........
1the given equation can be written as 2x - 3 + x -1x-1 = 6x2 - x - 6x - 1
→ 3x2 - 2x - 1 = 0
b2 - 4ac i.e, 4 + 12 = 16 >0
hence 2 real roots
so (b) [1]
1if a ,b ,c r roots of x 3 - 3 x2 + 3x + 7 =0 then
(a-1)/ (b-1) + (b-1)/ (c-1) + (c-1) /(a-1) =?
ans 3w2( w is cube root of unity)
39We have to round off 5.87532 ft to two figures.
≈ 5.8753
≈ 5.875
Now when the digit to be dropped is 5, followed by digits other than zero, then the preceding digit is raised by 1. If 5 is followed by zeroes, the preceding digit is - (a) left unchanged when even, (b) raised by one, if odd.
So ≈ 5.88 ft.
39I just used my equation solver(made one in C++ lol), that equation has two real roots x = -0.92 and x = 1.08. x = 1 is not a solution as it is not in the domain of the function.
1the max distance from origin of co ordinates of point z satisfying l z + 1/z l = a is ?
ans 1/2{ ( √a2+4 ) + a }
1@ cute cat i m nt getting this ques plz post ur solution..................
1Thanks a lot Akshay for sharing your experience. I'll really have to do it fastly.. I couldn't even complete 90 questions of AIEEE in 180 mins.. barely got time for doing maths.. will have to improve to save my already-sinking-ship.
1does all centres at a particular time giv all students the same questions?????
1no Rohit..each one gets a purely unique set of questions..which one be repeating unless there are 108 candidates , which ofcourse is not there [1]
1i am working from arihant bitsat book and they have given a unique code for taking test ol with that book. I think its gr8......... [1]
try it
11i had provided the link earlier but the thread was wrong...sorry...posting it here again...
http://bitsat.resonance.ac.in/login.php
2 free online tests are available....
you can register with an e-mail id......
since talks were on regarding the online test so posted it here...
1those resonance tests are quite tough...Most questions are JEE level.
1anyone who finds BITSAT sample papers
plz post their links here
it would be very helpful to all
specially those software type sample papers(BITSAT software)then that would be gr8
plz give links of all the sample papers here
1TIP #1:analyze about those 10 extra questions,see the number of questions u leave and the time u r left with in the sample papers.if u leave 15-18 questions with 10 min remaining go for xtra questions filling randomly those 15-18 questions,if say at least 3 questions are right out of 15,which is more than 50% probability then u get -3 marks and in those 10 extra questions(which are of same difficulty level based on PCM),u can get 5 questions and so 15 marks,net gain of 12 marks
Speed is the key!!
39Speed is the damned key for all these exams isn't it...BITS mein toh chaar sections honge...teen ghante mein mera PCM khatam nahi hota how will I manage BITS??