1evaluate limit x tends to '0' (sin(pi(cos square x)/x square
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1@ Athenes .... i know many websites... but target iit is best (for jee)
@a1b2c3,
\lim_{x\rightarrow 0}\frac{sin(\pi cos^{2}x)}{x^{2}}=\lim_{x\rightarrow 0}\frac{sin(\pi -\pi cos^{2}x)}{x^{2}}=\lim_{x\rightarrow 0}\frac{sin(\pi sin^{2}x)}{x^{2}}\times \frac{\pi sin^{2}x}{\pi sin^{2}x}
Ans : \pi
