second innings Qs

PHysics:
1>A motorcycle is going on a overbridge of radius R.The bike is acsending the overbridge with constant speed,then the normal rxn on it :
a)increases b)decreses c)remains same D) fluctuates

2>A rod of length L is pivoted at 1 end and is rotated with uniform ω .let T1 an dT2 be tensions at pts L/4 and 3L/4≤.Then THe inequality between T1 and T2 is:??

Old Question:
3> Train A runs frm east to west,pressing the track with force F1 and Train B,pressing the tack with F2(of same mass) frm west to east at same speed along equator:
a)F1>F2 b)F!<F2 c)F1=F2

PLZ GIVE THE LOGIC ALSO.

CHEM:How to know that a rxn proceeds in forward direction by looking at it??
for e.g:

a)SnCl4+Hg2Cl2--->SnCl2+2 HgCl2
b)NH4Cl+ NaOH-----> water+ ammonia +NaCl

Maths:
The population rises @ 5% every yr. In how many yrs will it double itself? [how to solve it using differntial eqn]

38 Answers

1
terror s ·

@vengence

N=mcosθ-mv^2/R isnt it?

1
Avinav Prakash ·

PHYSICS:

An uniform chain of length L and Mass M overhangs a horizontal table with 2/3 rd part on the table.FRiction co-eff bteween table and chain is μ.Find the work done by friction during the period the chain slips off the table.

39
Pritish Chakraborty ·

The chain being uniform, its mass per unit length remains constant.

Total weight = Mg
Weight of part on table = 2Mg3

Now we take the part of chain on the table as a point mass. This is equivalent to using the center of mass of the chain on the table(which behaves as if all the mass is concentrated there).
The COM of the part on the table is located at L3.
So to take it off the table, it has to travel L3 distance opposite to the force of friction.
Friction f = μN = μ x weight = μ x 2Mg3

Work = Force x Distance x cos180°
= 2μMg3 x L3 x (-1)
= -2μMgL9 units.

1
Avinav Prakash ·

thanks pritsh...dont know why i cudnt do it!!!!
Q> 3x-3-[3x-3]+ sinÎ x2
Find the period.[.]=GIF

Q>f(x+y, x-y) =xy. Find the AM of f(x,y)
and f(y,x).
.

106
Asish Mahapatra ·

Q. Let x+y = a
x-y = b
then f(a,b) = (a+b)*(a-b)/4 = (a2-b2)/4
=> f(b,a) = (b2-a2)/4

so, AM of f(a,b) and f(b,a) = 0

Q. y= {3x-3} + sin(pix/2)

period of {3x-3} = 1/3
period of sin(pix/2) = 2pi/pi/2 = 4

so, period of function = lcm = 4

39
Pritish Chakraborty ·

Asish does an LCM exist for a number like 1/3 with any other natural? I'm confused..

106
Asish Mahapatra ·

1/3 * 12 = 4
and 4*1 = 4

so lcm does exist

1
Shirsa Aich ·

for 3 it should be a as for the train running from west to east its apparent wt decreases due to increase in centrifugal force as it rotates in direction of earth.so it applies less force.but for train running from east to west this doesnt happen so it applies less force.so F1>F2

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