IIT JEE 2009 P1 Q26

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Tangents drawn from the point P()1.8) to the circle x²+y²-6x-4y-11=0 touch the circle at the points A and B. The equation of the circumcircle of the triangle PAB is

A) x²+y²+4x-6y+19=0
B) x²+y²-4x-10y+19=0
C) x²+y²-2x+6y-29=0
D )x²+y²-6x-4y+19=0

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4 Answers

Lokesh Verma ·2009-04-11 20:45:18

[url=http://iitjee2009solutions.targetiit.com]Solution Key with Question Paper of 2009 IIT JEE[/url]

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Lokesh Verma ·2009-04-12 03:18:08

correct answer is B because no other circle passes thru (1,8)

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kamalendu ghosh ·2009-04-12 07:39:22

yes B

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greatvishal swami ·2009-04-12 07:50:06

B
[4]

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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IIT JEE 2009 P1 Q26

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