IIT JEE 2009 P2 Q24

I_n=\int_{-\pi}^{\pi}{\frac{\sin nx}{(1+\pi^x)\sin x}}.. n=0,1,2.....

then

A) In=In+2
B) \sum_{m=1}^{10}{I_{2m+1}}=10\pi
C)\sum_{m=1}^{10}{I_{2m}}=0
D)In=In+1

3 Answers

1
kamalendu ghosh ·

A,B,C?

1
voldy ·

yes that's right.

11
rkrish ·

yup.......correct

I0 = 0
I1 = Î
I2 = 0
I3 = Î
.
.
.
So, Ans : A,B,C

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