a math beauty

Several successive number was written in a row.Determine the least value of the number of this sequence such that: there exist a way to order it again such that all 3 adjacent numbers(ie written one -next- the other) have sum which is divisible the previous number and the last number of this sequence is odd!

well this is not for jee, just a woonderful question which i could not keep without sharing

9 Answers

1
gagar.iitk ·

LEAST VALUE IS FOUR AND NUMBERS ARE 2,3,4,5

1
gagar.iitk ·

BUT I DONT THINK MY ANS IS RIGHT

1
gagar.iitk ·

THIS SHOULD NOT BE THAT EASY

1
gagar.iitk ·

mathematics can u post ur ans

11
Mani Pal Singh ·

or it is 0,1,2,3

39
Dr.House ·

nahiin bhaiyan yeh mujhe nahiin aaya

1
gagar.iitk ·

@ Nishant can u plz help us out

62
Lokesh Verma ·

I did not understand the language of this question :(

1) I mean what is that we have to find (The number of ways or the numbers themselves or the least number)

From what I understood it should be

1, 1, 1, 3

rearrange

to get 3, 1, 1, 1

last digit is odd. The last 3 are divisible by the number preceeding them!

but i am not sure if this is what the question asked for!

11
Mani Pal Singh ·

DICTHUM MERE BHAI
ISKA ANSWER TO BATA DE!!!!!!!!!!!!!!!

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