top three horses

many of you have done this

There are 25 horses and 5 race course. that means you can run atmost 5 horses in one race.

What will be the number (minimum) of races required to find the top 3 horses (top means which runs fast)

Those who already know this leave it for sometime :)

34 Answers

13
Avik ·

@JAi Hind.... I thot a horse had 4 legs in all...was i wrong? ;O

1
aposlil ·

I got 9 tries..

1
mayank586 ·

sir i think the answer is 12
first we shld have 5 races & eliminate 10 horses by selecting top 3 frm each
now we have 15 left
so we can have 3 races to select top 3 of each & eliminate 6 horses

races till now 8
now we have 9 more to go
we can have now 2 races 1 ith 5 & one with 4 horses
select 3 frm each

10 till now

have a race between 5 horses & let the 3 winners race with the other resting one

so total no 12
arshad g luks r8 to me

1
Jagaran Chowdhury ·

@illuminati , post the answer at least if not the soln.

39
Dr.House ·

answer has already been given in #18 dude..

always read complete thread before asking

39
Dr.House ·

First you run each group of 5 in a race, for 5 races total. Then, in the 6th race, you race the champions, to get positions(ranks) for all 5 of those.

they can be x1 x2 x3 x4 x5

y1 y2 y3 y4 y5

z1............................

t1............................

u1..............................

Now, we know the fastest among all is is x1.

The three fastest horses, in order, could be x1,x2,x3 or x1,x2,y1 or x1,y1,y2 or x1,y1,z1.

Race x2,x3,y1,y2, and z1 to determine the 2nd and 3rd fastest horses

21
omkar ·

[5]

1
Shahbaz Ali ·

fine work JAI HIND
hahahahahaha!!!!!!!!!!!!!!!!!!

23
qwerty ·

why isnt the horse getting tired ??lolz

1
Arshad ~Died~ ·

i dont think its possible sir in 7 tries.....i got it in 12

1
nidhi Govindraju ·

6 race have to be conducted.

5 to get the top 5, and then a match betwee the top 5. To get the top 3..........

6
AKHIL ·

well yes a strange horse indeed
thats why not gettin tired perhaps( 2 legs only)
lol:D

71
Vivek @ Born this Way ·

If this horse gets in the race, then Only 1 One match and we have TOP 1. :P

6
AKHIL ·

lol

:D

1
subha1432 c ·

I will Load a Gun and Shoot in air which three horses will escape first they will be the winner.
No race is required. Prob Solved. ha ha

1
shubham_pandey Pandey ·

hmmm...
i think i got it after making the five groups of all the top 3 horses in each group we can make them race in pairs like all the third ones in 1 group all the 2nd ones in 2nd group and all the first ones in another group. The winers of each group compete to find the final positions

71
Vivek @ Born this Way ·

Better Clear the area and race them all at once.!

1
Jagaran Chowdhury ·

sir, why did u pick top 3 from each group. the 4th horse in one group may be faster than third of another.didn't get it,sir

1357
Manish Shankar ·

there is some fault here

how do you know that the second in each group are not as fast as first in other group

1
Jagaran Chowdhury ·

is the question such that all horses have to compete against each other then the answer is wrong

1357
Manish Shankar ·

you have to find the fastest 3 from the 25 horses

1
Jagaran Chowdhury ·

25c2 .race them in sets of two .is it correct now ,sir?

1357
Manish Shankar ·

your first approach was right, think in that way only

1
Jagaran Chowdhury ·

is the answer 5,sir.

race them in 5 groups. note their timings, get the top 3

1357
Manish Shankar ·

Oh I forgot to tell you that you don't have stopwatch :(

1357
Manish Shankar ·

Hint:

First race them in 5 groups and pick top 3 from all the groups. So now you know the top 3 from all groups

what next?

1
Jagaran Chowdhury ·

is the answer 6

5 races with 5 horses .select the toppers from the 5 races and race them again to decide top 3

1357
Manish Shankar ·

but 4th will always be behind the 3 horses. So we can easily eliminate 4th one

1
Jagaran Chowdhury ·

sir ,what i'm saying is the 4th on of a particular group may be faster than chosen ones of another group.it is not going to be behind them

1
RAY ·

yes bro jagaran is right....if u r saying dat the second of a particular group can be faster than 1st of another group...then the 4th of a particular group can also be faster than the 1st or 2nd of another group....

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