05-03-09 Find the remaining length!

This is a very very very very old and well known thing of higher mathematics...

Though I am giving you a very simple part or the simple part of that thoery...

A line is of length 1.

1/3rd of the segment is removed from the middle.

From the remaining parts, 1/3rd fo the remaining lengths is removed again...

This process is repeated again and again...

What is the total length removed/Remaining?

16 Answers

21
tapanmast Vora ·

is da ANSWER = 0.5

39
Dr.House ·

is it the sum of the series \frac{1}{3} + \frac{2}{9} + \frac{4}{27} +\frac{8}{81} + ...................

39
Dr.House ·

i am talking abuout removed length

21
tapanmast Vora ·

yah!

hum dono ne same socha....

now jus subtract this infinte GP frm 1..... U'll get 1/2 as da ans!!!

62
Lokesh Verma ·

Fir pagla gaye

1
Akand ·

ya tapan deserved a pink...................but i dint understand logically??? hw wud half remain???

62
Lokesh Verma ·

that is the interesting thing akand..

it is such a huge gap from our understanding of intervals...

it is one another huge step..

that is why i thought it woudl be interesting to show this result at this stage :)

1
skygirl ·

this is someting like the paradox that in a race the runner can never reach the end line...

1
Akand ·

sky.......wat do u mean a runner can never reach d endline?????

1
chemistry organic ·

i found the sum it came 1......not 1/2........nishant chacha .....

21
tapanmast Vora ·

fir se ∞GP ka sum karo!

a = 1/3; r = 2/3; S = a/1-r

1
chemistry organic ·

ya a/1-r=(1/3)/1-2/3=====1.

21
tapanmast Vora ·

hey this is a big controversy!!!!

kal sir ko puchhna padega.......

bcoz 1/3 + 2/9 > 1/2

to half aane ka to koi question hi nahi aaata.......

and as chem said S(GP) = 1 ==> LOCHA...... [3] LOL

1
suraj5 ·

IT IS 16/81. BUT CANT GET NISHANTS CONCEPT BEHIND THAT.

62
Lokesh Verma ·

No controversies..

i went mad this was another example.. neend me i explained something different altogether ;)

;P

21
tapanmast Vora ·

SIR, to iska ANS kya hoga? ANS = 0 [5][5]

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