1-7-09

BITSAT 2015 Help › Question Of the Day questions › 1-7-09

Find the least positive value taken by 21x+12y+15z where x,y,z \epsilon Z

#Miscellaneous #Question Of the Day

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8 Answers

341

Hari Shankar ·2009-07-07 00:26:40

Is this a doubt or a challenge?

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Celestine preetham ·2009-07-07 00:48:17

ans is 3

now juniors try provin it :)

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Honey Arora ·2009-07-07 01:33:31

it wld cm by taking x=0,y=-1 and z=1
i don't know hw to prove it.......wld u mind posting the proof

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24

eureka123 ·2009-07-07 02:49:37

@bhat sir...its not my doubt.....just wanted to make students aware of the concept used here.....

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eureka123 ·2009-07-07 02:50:51

u r rite cele.....(no doubt i expected the right answer from u...[3])

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Celestine preetham ·2009-07-07 06:09:16

@ honey do u observe
the function is of form 3Î»

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341

Hari Shankar ·2009-07-08 01:20:12

gcd's definition

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eureka123 ·2009-07-08 06:59:01

yeah cele is rite............
the concept was
The least positive value of ax+by+cz where x,y,z \epsilon Z and a,b,c \epsilon N is the gcd of (a,b,c).

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

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