18-10-09 Sum of the Infinite series..

Find the sum of this infinite series

\sum_{0\leq i\neq j\leq \infty}{\left(3^{-i}\times 3^{-j})}

16 Answers

4
UTTARA ·

S = 1 / 30+0 + 1/3(1)+(1) +.............+∞

= 1/(1-1/32 )

= 9/8

3
msp ·

but i≠j na

62
Lokesh Verma ·

Uttara you have solved the other one.. where i=j

;)

4
UTTARA ·

Sorry I mistook the qs

Any hint for the right approach ??

62
Lokesh Verma ·

yeah..

What you have done is a subset of the work needed :D

3
msp ·

Reqd sum=9/64 is this rite.

341
Hari Shankar ·

to get some idea on how to proceed, look at the derivation of the sum of divisors of a number.

62
Lokesh Verma ·

no sankara.. you have missed it by a whisker

1
Anirudh Kumar ·

sir is

S= 9/4 correct .

using sum of infinite terms of a G.P

keeping i =0 varying j from o to ∞
keepint i=1 and varying j from o to ∞

i.e

S= 1/30{ 1/30+1/31+...+1/3∞}
+1/31{ 1/30+1/31+...+1/3∞}
+...

62
Lokesh Verma ·

anirudh you have also missed out something.. see more closely..

1
Anirudh Kumar ·

sir

i≠j .
thus from my solution i have to subtract those cases of
i=j

62
Lokesh Verma ·

yup.. so the final answer is?

1
riya ·

the answer is 3/4 am i correct

106
Asish Mahapatra ·

if anirudh's calc is correct,

the final ans is S - [(1/30)2 + (1/31)2 + ...]
= 9/4 - 11-1/9
= 9/4 - 9/8
= 9/8

verification of anirudhs calc
S = (1/30 + 1/31 + 1/32 + ... )2
= (11-1/3)2
= 9/4

1
Anirudh Kumar ·

S =
9/4-9/8
= 9/8

sir this answer is same as @uttara answers so i got a little Confused

62
Lokesh Verma ·

There are some more proofs.. can you think of a couple more?

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