3the potential of the capacitor plate is V=Enetd
Enet=Q/2ε0A-q/2ε0A
from the potential expression it can be proved dat CV is not equal to q
A parallel plate capacitor of Area A and seperation D is given charges Q and q on the two plates..
Will CV=q work?
Comment?
How do we find V?
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9 Answers
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62yes sankara that is correct.. but then how do u fidn the V now?
62@sankara.. you are pretty close..
@eureka.. No we are not doing that.. There is no connection that is taking charge from one plate to another..
39the thing is we will have the charges on the inner side of plate as
Q-q/2Aε
and the ineer charge on the other plate will be same as this but with a negative sign.
therefore the potential is Q-qD*/2Aε { assuming that Q>q}
3sir can u check i have a feeling the formula for the field shud be changed and i have edited dat sir
62no Bhargav and sankara.. you have found electric field....
You need to find the potential!
@eureka.. There are only 2 parallel plates.. there is no circuit.. so there is no question of charge flowing!
62but eureka.. the charges are not connected!!
What you are saying will effectively mean that when we have charges Q and -Q .. then they will redistribute to 0 charge on both the plates! :O
24oh yesss.......sorry..............i will delete above posts.........