in adiabatic compression decrease in volume is assosiated with
a)inc in temp n decre in pressure
b)decr in temp n incre in pressr
c)decre in both
d0inc in both

1
prateek punj ·

yaar see.....

T1/T2=(V2/V1)Î³-1....

if u take Î³=1.66 i.e. for a monoatomic gas....

T1/T2=(V2/V1)0.66

and since V1>V2.....

V2/V1<1.....

THIS IMPLIES.....

(V2/V1)0.66<1

1
Anuj Kumar ·

gamma always lies between 1 and 2 only never equal to both due to its relation with degree of freedom.

1
Tushar Negi ·

its D

AS IN ADIABATIC COMPRESSION PRESSURE INCREASES AND TEMPERATURE ALSO INCREASES

MORE LIKE A HEATER

BUT NOT EXACTLY

1
vector ·

see ma other doubts too

1
prateek punj ·

[51]..............

1
MATRIX ·

[54]....................

1
prateek punj ·

in that case we cann't be damn sure about the answer for sure....

1
vector ·

i meant to say a polyatomic gas

1
prateek punj ·

n kahan se aa gaya....it's adiabatic.....n=Î³.....

1
vector ·

bt how cud u be sure fr all d gases i mean monoatomic hasmax value ofÎ³ if n ki value be 1000000000000000then

1
vector ·

ven i thought d same bt ans provided is d

1
vector ·

arrey yaar suppose Î³=1.123
Î³-1=.123
frraction ki power 0.123 can be greater thn 1 na i hpe u understand[1]

1
prateek punj ·

Î³=cp/cv....

yaar can cp be equal to cv

1
vector ·

bt how u saw Î³-1
i mean v2/v1is a fraction
n if suppose Î³=1. sumting then d ans ll be reversed

1
prateek punj ·

i was just correcting ankit....

1
ANKIT MAHATO ·

see my post ... last one !

1
vector ·

prateek b option mein pressure inc ho raha hai

1
prateek punj ·

yaar pressure bhi toh increase hoga.....

V is decreasing....

PVÎ³=constant.....

1
ANKIT MAHATO ·

P1V1Î³ = P2V2Î³

P1V1Î³ / P2V2Î³ = 1

P1V1 / P2V2 = (V2/V1)Î³-1

T1/T2 = (V2/V1)Î³-1

V2/V1 is a fraction ...... so T2 final temp is more than initial and haan volume is decreasing so pressure increases ... oops i did a silly mistake !.
ans is D