yup u got the catch .. gud yaar ...!! try the other sum ..
f(x) is a bijective function .. g(x) is inverse of that function .. f '(x) = 1/ (1 + x2009)
find g ' (x) in terms of g(x) ?
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f(x) is a bijective function .. g(x) is inverse of that function .. f '(x) = 1/ (1 + x2009)
find g ' (x) in terms of g(x) ?