another in normal reaction

normal reaction between collar and track is
√(mg)²+(mv²/R)²

so frictional force acting will be μ_k√(mg)²+(mv²/R)²

so mdv/dt=-μ_k√(mg)²+(mv²/R)²

dv/dt=-μ_k√(g)²+(v²/R)²

dv/ds*ds/dt=-μ_k√(g)²+(v²/R)²

vdv/dt=-μ_k√(g)²+(v²/R)²

.....(correction with a minus sign)

Solve it to get 's'

Haven't taken gravity free space as in that case only normal reaction will be mv²/R and as μmv²/R will decrease v and hence normal reaction will also so when v→0 the force also→0 so it will take infinite time to stop...

The worst ever answer which i had got ever.. is definitely wrong as in phys answers are always simple.. :(

s=(R/2μ).ln((√v₀+√R²g²+v₀)/Rg)

[4] isko sab bhula gaye...

sahi answer to de do koi...

@shankara.. :eng: someone give correct answer..

v²Î¼k/R = -vdv/dx!!!!!!!!!!!!!

μkx/R = ln (0)

x = R /μk.................

defently rong!!!!!!!!!!!!!!!!!! rite im half asleep [13]

U have not taken gravity.. :O

horizontal usuall means to neglect gravity ........ !!! it cant be soo complex!!!!!!!!

sankara answer ennna????????

wait i will post the ans tomorrow.

but i think abi's soln is rite.

are aisa kaha ki horizontal matlab neglect gravity...

and who is abi??????????....................