2 Answers
rahul nair
·2010-02-28 05:57:37
2k@L/4=k@l/2 =restoring torque
k@l/2=ml2a/12....(a----angul. acc)
hhence, T=2pi√m/6k
2k@L/4=k@l/2 =restoring torque
k@l/2=ml2a/12....(a----angul. acc)
hhence, T=2pi√m/6k