ncreasing the frequency will decrease the refractive index of t....
it should be opposite..
What will happen to angle of min deviation in case of prism if we change frequency of light..
lol ...
in my mind i assumed that it is increased.. but is it r8..
pata nahi-> i don't know
n = A + B/λ2 .
so put this in the eqn for the R.I
n = sin (A+D / 2) / sin(a/2)
now . well cross multiplying , we get some constant.+ nB/λ2 = sin ( A+D)/2 .
then we know that . v=fλ . so we get . that as we increase f , the D increases no ? I don't know whether this's right.
ncreasing the frequency will decrease the refractive index of t....
it should be opposite..
i know a relation
μ=k+B/λ2 k,B are +ive constants.i think this relation is know as cauchys formula
λ=c/ν
increasing the frequency will decrease the refractive index of the prism and therefore it decreases the minimum deviation angle
ok but u didnt specify whether the u are increasing or decreasing the frequency
A.D = d@/dA
here @ = angle of minimum deviation
and A.D inversely proportional to the cube of the wavelength
i think got it..
λ decreases so μ increases.. hence angle of min dev.. increases
angular dispersion will change ...now as it is related to angle of minimum deviation , it will also be affectd