1
dinks007
·2010-05-20 12:25:59
sorry thats not the answer.....
1
Manmay kumar Mohanty
·2010-05-21 00:35:39
i must be like this i guess if correct
2C + 2H2 → C2H4 - 1400.5 KJ
2C + 3H2 → C2H6 - 1558.3 KJ
C2H4 → 2C + 2H2 1400.5 KJ .............(1)
2C + 3H2 → C2H6 - 1558.3 KJ .............(2)
Solving (1) and (2) we get
= C2H4 + H2 → C2H6 - 157.8 KJ
NOt sure if correct ?
1
rahul1993 Duggal
·2010-06-11 04:08:07
using Hess's law we can write the foolowing eqns
C2H4 + 3O2 → 2CO2 + 2H20 ΔH=-1400.5 KJ/mol
3H2O + 2CO2 → C2H6 + 7/2O2 ΔH= 1558.3 Kj/mol
H2 + 1/2O2 → H2O ΔH=-286.5 Kj/mol
adding the above, we get req eqn and ΔH°H = -128.7 KJ/mol