if a six digit no is selected at random its sum should be odd or even no
therefore required prob=
n(favourable outcomes)/n(elements in samplespace)
A number of six digit numbers are written down at random.Probability that sum of digits is even is
there are two elements is sample space even or odd and fav is even thats why 1/2
if a six digit no is selected at random its sum should be odd or even no
therefore required prob=
n(favourable outcomes)/n(elements in samplespace)
priyam but then in ur exp u dint mention that they shud be equally favourable sample points. in this case they are but not wen say consider prime nos