simple relation to prove!

Prove that n*(n+1)*(2n+1) is divisible by 6, for any n>0

1 Answers

Sriram Sankar ·

let p(n) denote the above express.

put n=1;

1*2*3=6 is divisible by 6.

let p(k) be true;

k*(k+1)*(2k+1)=6U(u here is any constant)


prove that p(k+1) is true


= 2(k^3)+9(k^2)+13k+6



is divisible by 6

hence p(n) is true for all natural numbers i.e n>0.

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