when u expand u will get a1x6296+a2x6295+...+a6295x2+a6296x+a6297
for sum of coefficient = a1+a2+...+a6297, which can be obtained by putting x=1
so sum of coeff. will be = (1+1-3)3148 = 1
what is the sum of coefficients of (1+x-3x2)^3148 ???????
please answer fast the exam is tomorow
when u expand u will get a1x6296+a2x6295+...+a6295x2+a6296x+a6297
for sum of coefficient = a1+a2+...+a6297, which can be obtained by putting x=1
so sum of coeff. will be = (1+1-3)3148 = 1