13Yeah -(c).
Successful cases-
i) Passes all 3.
ii) I-Pass, II-Fail, III-Fail.
iii) I-Pass, II-Pass, III-Fail.
P(i)+P(ii)+P(iii) = 1/2
Which gives-
1/p = (3q+1)
Option (c) satisfies the above condition.
A student appears for test I, II and II. The student is successful if he passes either in tests I and II or test I and III. The probabilities of the student passing in tests I, II and III are p, q and 12 respectively. If the probability that the student is successful is 12 then
a. p=q=1
b. p=q=12
c. p=1, q=0
d. p=1, q=12
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3 Answers
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