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an electric bulb rated 50W at 100V is used in a circuit having a 200V supply. What resistance R must be put in series with the bulb so that then bulb delivers 500W?

4 Answers

1
Pratyay Patra ·

TH ANSWER IS 10

1
Pratyay Patra ·

TH ANSWER IS 10

1
Bunnie Boy ·

I=P/V

I=500/10=5A

Resistance of bulb,R1=100/5=20 ohm

Resistance,r to be connected in series,

5A=200/R1+R2

R1+R2=200/5

R1+R2=40

20+R2=40

R2=20 ohm

1
Bunnie Boy ·

This answer is for 500W not 50 W

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