bad vectors

let foot of the perpendicular from (5,1,3) to the given line be A.

coordinates of A are (3,7+t,1+t)

so direction ratios of line perpendicular to given line is (-2,6+t,t-2)

since these lines are perpendicular we get t=-1

so point is(-2,5,-3) so distance of point from the line is √61

wrng hai

neways i gt d method thanks

so direction ratios of line perpendicular to given line is (-2,6+t,t-2)

since these lines are perpendicular we get t=-2

so point is (-2,4,-4)

. i think thats where i went wrong