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5 Answers

6

AKHIL ·2011-04-04 05:04:35

its a JEE 2008 quesn !!!
oofff............JEE 2008 was really very hard man!!!:(

(PS) (ST) = (QS) (SR)

now use AM > GM

1/2 ( 1/PS + 1/ST ) > 1/ √(PS) (ST)

1/PS + 1/ST > 2/√(QS) (SR)

now if x+ y = k (a constant ) , then xy is max. when x = y = k/2

thus (QS ) (SR) < 1/4 (QR)²

1/(QS ) (SR) > 4/(QR)²

thus , 1/PS + 1/PT > 2âˆš 4/(QR)² = 4/QR

so B and D r correct..

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janardhan reddy ·2011-04-04 05:38:30

how PS.ST=QS.SR?

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janardhan reddy ·2011-04-04 06:01:30

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11

Joydoot ghatak ·2011-04-04 07:00:32

apply, similarity in triangle PSQ and TSR.
angle PQS = angle STQ
and angle PSQ = angle TSR.

thus,
triangle PSQ and TSR are similar
thus, PSSR = QSST.

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6

AKHIL ·2011-04-04 09:37:12

this is so coz these points r concyclic...........

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Basic Integral Calculus Operators Symbols Matrix Cases

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