If the line y-√3x+3=0 cuts the parabola y2=x+2 at A and B,then PA.PB is equal to (P≠(√3,0)
Solution as in book
(y-0)/(√3/2)=(x-√3)/(1/2)=r
On solving with y2=x+2
3r2/4 = r/2 +√3 +2
PA.PB=|r1r2| = (4(√3+2))/3
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2 Answers
62See the things they have done is tried to express the equation of the given line in a parametric form.... relating to the point P (WHich coincinenteally lies on the line!)
Then they have used the r from the parametric form to solve the rest..
Form used:
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x-x1=r cos theta..
(y-y1)=r sin theta