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Prove that from a point (a,b) of the circle x(x-a) + y(y-b) = 0, two chords, each bisected by the axis of x, can be drawn if a2>8b2

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21
omkar ·

so x1,-b lies on the circle.

thus it should satisfy the equation x2+y2=xa+yb

=> x12 + b2 = x1.a - b2

=> x12 - x1.a + 2b2 =0

since x1 should be real...

therfore, D> 0

so, a2 > 8b2

proved

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