repeated pbm but simple for others

What is the radius of the smallest circle that contains both of the circles x2+y2=4; and (x-3)+(y-3)2=9 ???

9 Answers

3
msp ·

no dear

1
pankaj sachan ·

answer will be (2+3√2+3)/2

1
Vivek ·

is it (5 + 3√2)/2?

3
msp ·

i have done a method and i cant complete it

let P and Q be two pts on the circle x2+y2=4 and (x-3)+(y-3)2=9 respectively and the diameter of the smallest circle shud be the maximum distance between P and Q

there P(h,k) and Q(p,q)

(h-p)2+(k-q)2=l2

and i dont know how to proceed after this and i have only two eqns but 4 knowns i cant find any other eqns can anyone find a ways to this method please post

and if u got any other method please post

3
msp ·

u both given correct ans
can u explain me

1
shubhangi ojha ·

i think it should be 5 units, draw the 2 circles on the coordinate plane nd u'ii find

1
Vivek ·

join (0,0) and (-3,-3) (the centres) extend it to meet the circles,you should get the diameter which is 5+3√2

3
msp ·

no but the correct ans was given by pankaj sir and vivek_aero

3
msp ·

tx da

Your Answer

Close [X]