Str Lines

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The ends of a rod of length l moves on 2 mutually perpendicular lines.Find the locus of the point on the rod which divides it in the ratio 2:1.

#Mathematics #Co-ordinate Geometry

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8 Answers

11

Gone.. ·2009-06-24 08:54:35

sum1 pls do this

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3

iitimcomin ·2009-06-24 08:55:37

HINT use trigo!!!

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iitimcomin ·2009-06-24 08:58:10

(3y/l)^2 + (3x/2l)^2 = 1 [takin point of intersection of those two[perp] lines as origin]

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1357

Manish Shankar ·2009-06-24 09:05:00

take the ends of rods as (x,0) and (0,y)

required point P is find the point (h,k) on the rod which divides the length in ratio 2:1

the put h, k in x²+y²=l²

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11

Gone.. ·2009-06-24 09:10:36

very nice idea manish bhaiya ... thank You ! :)

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11

Gone.. ·2009-06-24 09:23:47

bhaiya ans is not matching :(

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msp ·2009-06-24 18:58:39

i think the ans will be an ellipse.

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1

Mirka ·2009-06-24 22:04:32

locus of the reqd point will be

(3x/2)² + (3y)² = L²

or

(3y/2)² + (3x)² = L²

It's an ellipse.

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Your Answer

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