1anyone???
The line 6x+8y=48 intersects the coordinate axes at A and B respectively.
A line L bisects the area and the perimeter of the triangle OAB where O is the origin.
Find the slope of this line.
Options are:
(a)\frac{10+5\sqrt{3}}{10}
(b)\frac{10-5\sqrt{6}}{10}
(c)\frac{8+3\sqrt{6}}{10}
(d) \textit{None of these}
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13 Answers
11bhai maine bhi yehi kaha tah
but chinmay said that this is wrong[17][17]
1It is not an isoceleous triangle...not necessary to pass through perpendicular bisector
62The line 6x+8y=48 intersects the coordinate axes at A and B respectively.
A line L bisects the area and the perimeter of the triangle OAB where O is the origin.
Find the slope of this line.
One suggestion
did you try this geometrically?
I think there is scope for getting an answer that way
x intercept is 8
y intercept is 6
now do some geometry... I am pretty confident that geometry with a bit of coordinate of course.. will help..
1let y=mx+c be the line... (c >0)
let C(0,c)
now it intersects d given line at P((48-8c)/(6+8m) , (48m+6c)/)6+8m))
(6-c)+PB = PA+8+c = 12...
also ar(ΔPBC) = 12 => 1/2.(6-c).((48-8c)/(6+8m)) = 12...
these two equations will give u d value of 'm' rite...!!!
This is a lengthy problem... so no one can post d entire solution here... try working urself...
and since i'm confident about akshay, his answer might b rite to a large extent... :)
hope dis hint helps... :)
- Akansha I have solved it in the same way as you said. But i am getting a cubic equation in c and getting the three values of c and m.So there should be three lines which are possible but ans is only one line possibleUpvote·0· Reply ·2018-09-22 11:26:18
62a straight line cannot pass thru all 3 sides..
so it will be such that the sum of 2 intersects is (6+8+10)/2=12
now if one of these is the side 6, it is cut at a and the other is 8 cut at 6-a or a+2
similarly try for others.. i guess it should be easy eliminations...
is this hint sufficient?