System Of Circles 3

Find the eq. of the circle which passes through the points (2,0) and (0,2) and orthogonal to the circle 2x2+2y2+5x-6y+4=0

6 Answers

1
Sridhar M ·

try it using the same method

take the stand form and substitute the points and then apply condition for orthogonal circles. you'll get 3 equations and solve them.you'll get the circle.

1
" ____________ ·

let equation of circle be

passes through ( 2, 0) and ( 0, 2 )

passes ( 2,0)
---1

passes ( 0,2 )

--2

solve des

and for orthogonality use
2gg1+ 2ff1 = c + c1

also u can consider those points as end of diameter

3
tormented ·

How can I solve 1 and 2 when there are 3 unknown values namely g,f and c

3
tormented ·

If I try doing it using the old method I am getting a relationship between g and f but not the values and the constant term is getting eliminated while the answer given is 7x2+7y2-8x-8y-12=0

1
" ____________ ·

solvin 1 and 2

u get g=f na ???

use it in orthogonality equation

3
tormented ·

Understood.
Thanks.

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