Test:183 QNo:4

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A football of mass m approaches at 10m/s and is kicked by the footballer such that it returns at 10âˆš2 at an angle of 45 degrees from its initial direction!
What is the magnitude of the impulse?

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Shubh ·2010-10-17 01:49:11

Can u explain why 2vi+vj? why 2v?

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jeetopper jee ·2010-10-17 09:20:18

Fdt=m{(10(2)^1/2*1/2^1/2)+m(10)}i+m(10(2)^1/2*1/2^1/2)j

=20mi+10mj

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qwerty ·2010-10-17 09:34:41

Impulse I = Î”p = m Î” v = m (v_final - v_initial )

v_final = 10 i + 10 j

v_initial= - 10 i

so I = m ( 20 i + 10 j)

| I | = √20²+10²

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Test:183 QNo:4

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