1here's d explanation:
et the mass of the bullet be m
so heat reqd to just melt=m*0.03*300+m*6=15m calories
Q=15*4.2*m=63m joules [what is the meaning of this line?]
0.75*(1/2)*m*v2=63m
v2=2*63/0.75
A lead bullet just melts when stopped by an obstacle. Assuming that 25 % of the heat is absorbed by the obstacle, find the speed of the bullet if its initial temperature is 27°C. (Melting point of lead=327°C, specific heat of lead=0.03 cal/gm/°C, latent heat of fusion of lead=6 calories/gm)
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