Test:33 QNo:6

IIT JEE Help › Disucss Test Questions questions › Test:33 QNo:6

lim(x→0) 1/x²-1/(xsinx)

#Miscellaneous #Disucss Test Questions

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3 Answers

1

shankyshanky shanky ·2010-02-16 16:42:59

explaination of q-06

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13

Avik ·2010-02-16 21:38:29

\frac{1}{x^2}-\frac{1}{x.Sin(x)} = \frac{Sin(x)-x}{x^2.Sin(x)}\\ \\ Use \ taylor \ series \ expansion\ , \frac{\left( x-\frac{x^3}{6}+...\right)-x}{x^2.\left(x-\frac{x^3}{6}+...\right)} \\ \\ \\ Which \ reduces \ to , \ \lim_{x \rightarrow 0} \frac{\left(\frac{-1}{6}+ x(...)\right)}{1- x(...)} = -1/6

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Anirudh Kumar ·2010-02-17 07:59:37

one other way is to apply L'hospital rule.

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

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