Test:351 QNo:44

\int_{\pi /6}^{\pi /2}{log(sinx)cotxdx}

6 Answers

1
°ღ•๓яυΠ·

Q44 a) -(log2)2/4
b) -(log2)2 c) -(log2)2/2 d) -(log2)2/8

1
°ღ•๓яυΠ·

put losinx=t
so ur int bcums

t dt

so itz
t^2/2

so log sinx d whole squre /2

11
Mani Pal Singh ·

integrate it by parts

Take the 1st function as log sinx and 2nd function as cot x

USE
∫cotx=lnsinx

i hope u will get ur answer
if still doubt persists then ask again!!!!!!

1357
Manish Shankar ·

(1/2)[(logsinx)2]pi/6pi/2=(1/2)[0-(log1/2)2]=-(log2)2/2

whats your doubt here

1
°ღ•๓яυΠ·

sirji answer c diye hai aapne

1357
Manish Shankar ·

to (c) me to -(log2)2/2 yahi option diya ha na

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