Test:351 QNo:47

lim(x→0) √1-cos(2Ï€x)/x

3 Answers

11
Anirudh Narayanan ·

HOW, VIVEK?

\lim_{x\rightarrow 0}\frac{\sqrt{1-cos2\pi x}}{x}\; =\; \lim_{x\rightarrow 0}\frac{\sqrt{2sin^2\pi x}}{x}

=\; \lim_{x\rightarrow 0}\frac{\sqrt{2}sin\pi x}{\pi x}\; \pi = \sqrt{2}\pi ????

11
Anirudh Narayanan ·

Oh.....ok...thanx vivek

1
Vivek ·

Edit:LHL≠RHL
so limit does not exist

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